Jamie2
- 17
- 0
The question is to classify/describe the following degenerate quadratic surface:
x2 - 2xy +2y2 - 2yz + z2 = 0
x2 - 2xy +2y2 - 2yz + z2 = 0
Write it as (x^2- 2xy+ y^2)+ (y^2- 2yz+ z^2)= 0Jamie said:The question is to classify/describe the following degenerate quadratic surface:
x2 - 2xy +2y2 - 2yz + z2 = 0
well that's the same as (x-y)2 + (y-z)2 = 0HallsofIvy said:Write it as (x^2- 2xy+ y^2)+ (y^2- 2yz+ z^2)= 0
Does that give you any ideas?
Jamie said:well that's the same as (x-y)2 + (y-z)2 = 0
but I don't know how to use that to help me describe the quadratic surface
I like Serena said:Hi Jamie! Welcome to MHB! :)
Did you know that a square is always at least zero?
Suppose the sum of 2 squares is equal to zero, what does that say about those squares?
Jamie said:That they are equal to each other?
Or that (x-y)2 = -(y-z)2
I like Serena said:That they are both zero!
If either of them would be not zero, the sum would be positive, and therefore not equal to 0.
Jamie said:right, I knew that too. But what does that mean for the equation's 3-dimensional surface?
I like Serena said:It means that $x=y$ and $y=z$.
Both are equations of planes.
The degenerated quadratic surface is where they intersect.
Where do they intersect?
Jamie said:on the y axis? is the degenerate surface just a line?
Both! The only way a sum of squares can be 0 is if each is 0. x- y= 0 and y- z= 0 which is the same as the z= y= x. That is the line through (0, 0, 0) and (1, 1, 1).Jamie said:That they are equal to each other?
Or that (x-y)2 = -(y-z)2