What Is the Connection Between Viscosity and Shear Stress in Perfect Fluids?

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SUMMARY

The discussion clarifies that a perfect fluid, defined by its inability to sustain shear stress, has a viscosity of zero. Specifically, the equation p_{yx}=2\mu \dot \epsilon_{yx}=0 illustrates that when shear strain rate (\dot \epsilon_{yx}) is non-zero, adjacent layers can move independently without internal resistive stresses. The misconception addressed is that the scenario described does not imply a zero shear rate but rather a condition where viscosity is absent, allowing for different velocities in adjacent layers. Additionally, the distinction between ideal fluids and perfect fluids is noted, with the former being a subset of the latter.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with viscosity and shear stress concepts
  • Basic knowledge of tensor notation in physics
  • Proficiency in mathematical expressions related to fluid dynamics
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  • Study the Navier-Stokes equations for real fluid behavior
  • Explore the differences between ideal fluids and perfect fluids
  • Learn about the implications of zero viscosity in fluid dynamics
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So the textbook I am reading says that a perfect fluid cannot sustain shear stress, or that p_{yx}=2\mu \dot \epsilon_{yx} =0, where \mu is the viscosity, and \dot \epsilon_{yx} is the rate of angular deformation. Then it says when \dot \epsilon_{yx} =0, this means that "two adjacent horizontal layers of a perfect fluid can move at different velocities without one layer affecting the other layer through internal resistive stresses." This seems to me, however, like what would happen if the viscosity were zero.

Can someone clear up my misconception?
 
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Viscosity is zero in a perfect fluid. The situation described is not ##\dot\epsilon_{xy}=0## but ##\neq 0##.

Edit: Why is \eps not a standard TeX command yet? :headbang:
 
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I think ideal fluids are a subset of perfect fluids, at least according to my book.
 

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