What Is the Correct Formula for Calculating Speed in Uniform Circular Motion?

Click For Summary
SUMMARY

The correct formula for calculating speed in uniform circular motion involves understanding the forces acting on an object at different points in the loop. For a pilot at the top of a vertical loop with a radius of 290 m, the equation v²/r = a - g should be used, where 'a' is the centripetal acceleration and 'g' is the acceleration due to gravity. At the bottom of the loop, the formula changes to v²/r = a + g, reflecting the direction of the forces. This distinction is crucial for accurately determining the speed of the airplane.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with centripetal acceleration concepts
  • Knowledge of gravitational force and its effects
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn how to apply Newton's second law in circular motion scenarios
  • Explore examples of forces acting on objects in vertical loops
  • Practice solving problems involving vertical circular motion
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of circular motion and the forces involved in vertical loops.

d.tran103
Messages
39
Reaction score
0
Can someone tell me how I am plugging this in wrong? And am I using the right equations? Thanks!

Homework Statement


A pilot is flying a vertical loop of radius 290 m, and at the top of the loop is pushing against the seat with a force of .25 "g's" {or Normal force = .25mg}. What is the speed of the airplane at that moment?

In the above loop problem, if at the bottom of the loop the pilot is pushing against the seat with 6.0 "g's", what is his tangential or linear speed?


Homework Equations


v^2/r = a-g


The Attempt at a Solution


I plugged everything in but keep getting a negative number that cannot be square rooted. This is what I'm plugging in. How am I plugging this in wrong?

v^2/290 = 9.8*(0.25) - 9.8
 
Physics news on Phys.org
My choices for part a are:
60 m/s
77 m/s
53 m/s
81 m/s

This makes no sense!
 
At the top of the loop the forces acting on the pilot are the seat pushing on him and gravity. Hence the total force is

F = mg + 0.25mg
= 1.25mg
also
<br /> F = ma = mv^2/r<br />

equate these two and resolve for v

At the bottom of the loop, again calculate the resultant force and use the same method to solve.
 
d.tran103;3188783 v^2/r = a-g [/QUOTE said:
Here use v^2/r = a+g.
Because a, v^2/r and g have the same direction
 
d.tran103 said:
v^2/r = a-g

Here use v^2/r = a+g.
Because a, v^2/r and g have the same direction
 

Similar threads

Replies
55
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
11
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K