What is the curvature of a graph at a point?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
deba123
Messages
4
Reaction score
0
Consider the curve which is graph of a smooth function $$ f : (a,b) → R$$. Show that at any $$ {x}_{0}\:s.t\:{x}_{0} ∈ (a,b)$$ the curvature is $$\frac{{f}^{''}({x}_{0})}{{(1+{{f}^{'}({x}_{0})}^{2})}^{3/2}}$$.
 
Last edited:
Physics news on Phys.org
Can you show us what you've tried so far so we know where you are stuck and can offer better help?