What is the Definition of Compactification for a Topological Space?

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The discussion focuses on the definition of compactification for a topological space, specifically the construction of a new space Y = X ∪ {p} with a topology τY. The conditions for U to be open in τY are outlined, emphasizing the requirement that X - U must be a compact closed subset of X when p is included in U. The participants clarify that proving (Y, τY) is compact necessitates understanding the open sets in τY and their relationship to the original topology τX.

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Flying_Goat
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Hi guys, I am confused about the definition of compactification of a topological space.

Suppose (X,τx) is a topological space. Define Y=X[itex]\cup[/itex]{p} and a new topology τY such that U[itex]\subseteq[/itex]Y is open if
(1) p [itex]\notin[/itex] U and U[itex]\in[/itex] [itex]\tau[/itex]X or
(2) p [itex]\in[/itex] U and X-U is a compact closed subset of X.

To prove that (Y,τY) is compact, it seems to require X-U in (2) to be compact under τY and not τX. That is if p[itex]\in[/itex] U, then any open covering {Vi}[itex]\subseteq[/itex]τY of Uc=X-U, has a finite subcover. But we don't even know what our open sets {Vi} are in the first place.

Any help would be appreciated.
 
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The induced topology of X as a subspace of Y is the same as the original topology of X (this is not obvious, but not hard to prove, just some definition chasing), so if we have
[tex]A\subset X \subset Y[/tex]

A is compact in the topology of Y if and only if it is compact in the topology of X
 
Ah, I see. Thanks very much.
 

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