The discussion revolves around calculating the density of the Earth using its mass, which is given as 5.97 e 24 kg. Participants are attempting to convert this mass into pounds per cubic foot, but there is uncertainty regarding the necessary volume for the calculation.
Some participants have provided guidance on the conversion process and emphasized the need for volume to calculate density. There is a recognition that additional information, such as the Earth's radius, is necessary to proceed, and some participants are considering the implications of insufficient data.
There is a mention of homework constraints, as the original poster indicates that they were not instructed to look up the Earth's radius, which raises questions about the completeness of the information provided for the problem.
964js7 said:Homework Statement
The mass of the Earth is 5.97 e 24 KG. If density = mass/volume, what would be the density of the Earth in pounds/ft(3)
Homework Equations
The Attempt at a Solution
5.97 e24 KG X 2.2 lbs x 1ft3/62.4lbs = 2.1 e23 ft3...
I don't know what to do after this.
LowlyPion said:Welcome to PF.
What have they asked for?
[tex]Density = \frac{POUNDS}{Feet^3}[/tex]
You have converted mass to pounds?
And then what?
What are the other numbers?
964js7 said:5.97 e24 KG X 2.2 lbs
Borek said:I suppose that was aimed at converting kg to lbs. For that you conversion factor unit should be lbs/kg:
5.97e24 kg * 2.2 lbs/kg = 2.2*5.97e24 kg*lbs/kg
Note, how kg cancels out.
964js7 said:The other property would be volume, but I don't know how to get it with the given info..
chroot said:Yes, you need the radius or diameter of the Earth, as well as its mass, to find its density. If those values are not given, then there is not enough information to answer the question -- unless, of course, you are expected to go look up the radius of the Earth yourself.
- Warren
964js7 said:Should I Just write, not enough info. on my paper? He didnt tell us to search for the radius.