bergausstein Messages 191 Reaction score 0 Thread starter Jan 1, 2014 #1 is this a difference of two squares? $\displaystyle x^{\frac{1}{4}}-y^{\frac{1}{4}}$
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 Jan 1, 2014 #2 Yes, if you write it as: $$\left(x^{\frac{1}{8}} \right)^2-\left(y^{\frac{1}{8}} \right)^2$$