MHB What is the Domain of Each Variable in a Rational Function?

  • Thread starter Thread starter mathdad
  • Start date Start date
AI Thread Summary
The discussion focuses on determining the domain of variables in rational functions. For the function y - 1, the domain is all real numbers (R). In the case of (2y)/(y - 1), the variable y cannot equal 1, leading to the domain expressed as D = {y | y ≠ 1}. The interval notation for this domain is (-∞, 1) U (1, ∞). Understanding these domains is essential for working with rational functions effectively.
mathdad
Messages
1,280
Reaction score
0
Specify the domain of each variable.

1. y - 1

Well, y can be any integer. So, the domain is R, where R = ALL REAL NUMBERS.

2. (2y)/(y - 1)

y - 1 = 0

y = 1

Let D = domain

D = {y| y CANNOT be 1}

Correct?
 
Mathematics news on Phys.org
Correct. :D

Can you state the domains using interval notation? It's a commonly employed notation that students should be able to utilize when stating domains/ranges, etc.
 
If memory serves me right, the interval notation is

y = (-∞,1) U (1,∞)
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top