What is the energy imparted to each electron in Compton-scattering at 87.0°?

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Homework Statement

Photons of wavelength 59.0 pm are Compton-scattered from a free electron in an aluminum block, at 87.0° from the original direction. What energy (in electronvolts) has been imparted to each electron?

Homework Equations

$\frac{h}{mc}$ = 0.0024nm for e^-
∇λ = $\frac{h}{mc}$ (1-cosθ)
hc = 1240 eV*nm

The Attempt at a Solution

I got as answer: 2.02 $\times$ 10⁴eV (its wrong):

∇λ = 0.0024nm *(1-cos(87°)) = 0.0023nm
λ₂ = λ₁+∇λ = 0.059nm + 0.0023nm = 0.0613nm
E₂ = hc/λ₂ = 1240eV*nm / 0.0613nm = 2.02 $\times$ 10⁴eV

 

[asdf12312]

figured out what i was doing wrong. nevermind