Paulo2014 Messages 79 Reaction score 0 Thread starter Mar 30, 2008 #1 Homework Statement (3x-5)/4 + (2-3x)/2 = (x-2)/5 Homework Equations The Attempt at a Solution I tried this and got x= 6.3 reacurring... but i don't think it is right...
Homework Statement (3x-5)/4 + (2-3x)/2 = (x-2)/5 Homework Equations The Attempt at a Solution I tried this and got x= 6.3 reacurring... but i don't think it is right...
rocomath Messages 1,752 Reaction score 1 Mar 30, 2008 #2 [tex]\frac{3x-5}{4}+\frac{2-3x}{2}=\frac{x-2}{5}[/tex] Multiply everything by 20 [tex]5(3x-5)+10(2-3x)=4(x-2)[/tex] Take it from here ...
[tex]\frac{3x-5}{4}+\frac{2-3x}{2}=\frac{x-2}{5}[/tex] Multiply everything by 20 [tex]5(3x-5)+10(2-3x)=4(x-2)[/tex] Take it from here ...
Paulo2014 Messages 79 Reaction score 0 Mar 30, 2008 #4 I multiplied everything by 40, not 20, and then went 10(3x-5) + 20(2-3x) = 8(x-2)
rocomath Messages 1,752 Reaction score 1 Mar 30, 2008 #5 Ok, keep showing your work and we'll look over it. I'm not going to do it for you. You can check if your solution is correct by plugging it into your original equation ... left should equal the right.
Ok, keep showing your work and we'll look over it. I'm not going to do it for you. You can check if your solution is correct by plugging it into your original equation ... left should equal the right.
Paulo2014 Messages 79 Reaction score 0 Mar 30, 2008 #6 I know. then I expanded everything to make it : 30x-50+40-60x=8x-16 Then I combined like terms to make it -30x-10=8x-16 Then I moved like terms to make it: -38x=-6 Which equals 6.3 reacuring... is that right?
I know. then I expanded everything to make it : 30x-50+40-60x=8x-16 Then I combined like terms to make it -30x-10=8x-16 Then I moved like terms to make it: -38x=-6 Which equals 6.3 reacuring... is that right?
Snazzy Messages 470 Reaction score 0 Mar 30, 2008 #8 Why are you dividing 38 by 6? You're trying to solve for the x.
Paulo2014 Messages 79 Reaction score 0 Mar 30, 2008 #9 Don't you divide by the number in front of x by the number after the equals sign to get the answer for x?
Don't you divide by the number in front of x by the number after the equals sign to get the answer for x?
Snazzy Messages 470 Reaction score 0 Mar 30, 2008 #10 No. For example: [tex]6x = 12[/tex] [tex]\frac{6x}{6}=\frac{12}{6}[/tex] [tex]x=2[/tex] This is really basic algebra.
No. For example: [tex]6x = 12[/tex] [tex]\frac{6x}{6}=\frac{12}{6}[/tex] [tex]x=2[/tex] This is really basic algebra.
Paulo2014 Messages 79 Reaction score 0 Mar 30, 2008 #11 But that is exactly what I did... -38x/-38= -6/-38
Paulo2014 Messages 79 Reaction score 0 Mar 30, 2008 #13 oh... i see what i did wrong... thanks for pointing that out...