1. The problem statement, all variables and given/known data When a diverging lens is held 12 cm above a line of print, as in Figure 26.29, the image is 4.1 cm beneath the lens. What is the focal length of the lens? 2. Relevant equations 1/di + 1/do = 1/f 3. The attempt at a solution 1/di + 1/do = 1/f 1/4.1 + 1/12 = 1/f f = 3.0559 cm What did I do wrong?