What is the force exerted by a falling chain on a table?

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SUMMARY

The discussion focuses on calculating the force exerted by a falling chain on a table, specifically when a uniform chain of mass M and length L is released from rest. The key equation derived is F = dp/dt = Mv + Mv', where dp represents the change in momentum. The participants emphasize the need to determine the mass of the chain in contact with the table as a function of its acceleration due to gravity (g) and to apply Newtonian mechanics rather than Lagrangian or Hamiltonian methods.

PREREQUISITES
  • Understanding of Newtonian mechanics
  • Basic calculus, particularly integration and differentiation
  • Familiarity with momentum concepts in physics
  • Knowledge of uniform mass distribution in chains
NEXT STEPS
  • Study the derivation of momentum equations in classical mechanics
  • Learn about the principles of free fall and its effects on mass
  • Explore the concept of mass per unit length in continuous systems
  • Investigate applications of calculus in physics problems
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Students studying physics, particularly those focusing on mechanics, calculus applications in physics, and anyone interested in understanding the dynamics of falling objects and forces in contact scenarios.

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Homework Statement


1. (30 points) A very flexible uniform chain of mass M and length L consisting of very small links is suspended from one end so that it hangs vertically, the lower end just touching the surface of a table. The upper end is suddenly released so that the chain falls onto the table and coils up in a small heap, each link coming to rest the instant that it strikes the table.

Find: (a) The force F exerted by the chain on the table at any instant, in terms of the weight of the chain already on the table at that moment.

When the chain falls, we know that T=0, and net force is Mg

Homework Equations


F=dp/dt=Mv +Mv'

Possibly CM?
R=(m1r1+m2r2)/(m1+r1)

The Attempt at a Solution


I know that we need to solve for the actual mass of the chain hitting the table as a function of its acceleration g, and that we need to likely integrate to find mass per unit length, so my attempt at this equation was
M/L=dL/dt
Mdt=dL*L

Then, once mass per unit length was found, we could put it in for M in the equation F=dp/dt=Mv +Mv', and solve for F. I'm just not quite sure I'm on the right track. My calculus teacher deliberately avoided applications in physics, so I'm really having a rough time setting up the differentials. *Note, we have to use Newtonian methods, not lagrange or hamiltonian. Thank you in advance!
 
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Momentum is a good place to start. What is the momentum ## dp ## of a small length of chain ## dl ## falling at velocity ## v ##?
 
The chain is uniform, mass per length is constant. The length on the table (and its rate of change) is not constant, but you can find it first from free fall.
 

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