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Homework Statement
A 230.0 kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the bear and the tree?
A 230.0 kg bear sliding down a vertical tree at constant velocity experiences a friction force equal to its weight due to the balance of forces. The gravitational force acting on the bear is calculated using the equation F = m * g, where m is the mass (230.0 kg) and g is the acceleration due to gravity (9.81 m/s²). Therefore, the friction force is 2256.3 N acting upward, countering the downward gravitational force.
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