What is the General Form of Solutions for the Schrodinger Wave Equation?

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The general form of solutions for the Schrödinger wave equation is expressed as ψ(x) = A sin(kx) + B cos(kx). This formulation arises from the stationary Schrödinger equation (SWE) in a system with no potential energy, represented as (-iħ ∂/∂x)²/2m ψ(x) = ħ²k²/2m ψ(x). The constants A and B are determined based on the boundary conditions of the system. Understanding the derivation of -k² is crucial for grasping the underlying principles of quantum mechanics.

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I'm learning how to solve the Schrödinger wave equation and I know that the solutions are of the general form:

[tex]\Psi[/tex](x) = A sin kx + B cos kx

This was given to us, but where did it come from? Is it the fact that the wave could be a sine or cosine wave, and the other constant multiplier (A or B) can then be set to zero using boundary conditions? Or is there something more complicated going on here?
 
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Hi.
ψ (x) = A sin kx + B cos kx
is derived from
ψ" (x) = -k^2 ψ (x)
which is derived from
(-i hbar ∂/∂x)^2/2m ψ (x) = hbar^2 k^2/2m ψ (x)
which is stationary SWE in the system of no potential energy with energy eigenvalue hbar^2 k^2/2m.
A and B are chosen to meet the boundary conditions.
Regards.
 
Ooooookay, that makes sense. I wasn't sure where (or even if) -k^2 came into play here, but now that you showed me, I should have seen it. I didn't even think of reducing h, but that makes a lot more sense. Thanks a lot for the response.
 

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