- #1

toddkuen

- 15

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My name is Todd and I have a posted a proof of Goldbach's Conjecture.

I have been looking around for a while to find a place to post it and this seems like a reasonable place to start. I have stopped by here before but never registered.

The proof is http://www.just-got-lucky.com/gc-083110-draft1.pdf" .

The proof is somewhat geometric, wolfram NKS-like, and does not use much advanced math

Perhaps someone will look - I understand that I am both new here and probably a crackpot but we all have to do what we feel we need to do.

So if there is a horrific glaring error please be at least somewhat kind.

The basic proof is fairly simple in concept:

I create a diagonal "table" where the diagonal is odd primes > 3 and under the diagonal all even numbers appear at the intersection of rows and columns.

I then derive a "counter diagonal" that shows, for a given even number, all the unique odd number pairs that can generate it.

I then eliminate all the non-prime odd pairs from this table and show that, with what's left, you basically have to violate Betrand's Postulate in order to contradict the conjecture.

I have been looking around for a while to find a place to post it and this seems like a reasonable place to start. I have stopped by here before but never registered.

The proof is http://www.just-got-lucky.com/gc-083110-draft1.pdf" .

The proof is somewhat geometric, wolfram NKS-like, and does not use much advanced math

*per se*so the concepts are much different than you usually see posted here.Perhaps someone will look - I understand that I am both new here and probably a crackpot but we all have to do what we feel we need to do.

So if there is a horrific glaring error please be at least somewhat kind.

The basic proof is fairly simple in concept:

I create a diagonal "table" where the diagonal is odd primes > 3 and under the diagonal all even numbers appear at the intersection of rows and columns.

I then derive a "counter diagonal" that shows, for a given even number, all the unique odd number pairs that can generate it.

I then eliminate all the non-prime odd pairs from this table and show that, with what's left, you basically have to violate Betrand's Postulate in order to contradict the conjecture.

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