What is the gravitational Field?

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Homework Help Overview

The discussion revolves around understanding the gravitational field produced by a thin spherical shell, specifically at a point located 1.4 m from its center. The context includes the application of the shell theorem and gravitational concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the shell theorem and flux arguments, with some suggesting a focus on visualizing the flux rather than relying solely on equations. There are attempts to clarify the nature of the gravitational field as a vector field and its implications at the center of the shell.

Discussion Status

There is an ongoing exploration of the gravitational field's value at the specified point, with some participants questioning whether the answer could be zero. Hints and references to the shell theorem have been provided, indicating a productive direction in the discussion.

Contextual Notes

Participants express uncertainty about the answer and the implications of the shell theorem, suggesting a need for further clarification on the topic. There is an acknowledgment of the importance of understanding the concepts before class discussions.

grouchy
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Hint: Use shell theorem and/or flux argument for a symmetrical shell.

A thin spherical shell has a radius of 3.4 m and a mass of 456 kg. The Universal gravitational constant is 6.6726 x 10^-11 N m^2/kg^2.

What is the gravitational field 1.4 m from the center of the shell? Answers in units of N/kg.

Attempt--
I tried this equations, a= - G(delta m)/ (x^2 + y^2)
 
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forget equations. picture the flux
 
grouchy said:
Hint: Use shell theorem and/or flux argument for a symmetrical shell.

A thin spherical shell has a radius of 3.4 m and a mass of 456 kg. The Universal gravitational constant is 6.6726 x 10^-11 N m^2/kg^2.

What is the gravitational field 1.4 m from the center of the shell? Answers in units of N/kg.

Attempt--
I tried this equations, a= - G(delta m)/ (x^2 + y^2)

The gravitational field is a vector field. The gravity at the center will be the integral of all the mass of the shell acting at that point through all directions.

Maybe read up a little about the Shell Theorem?
http://en.wikipedia.org/wiki/Shell_theorem
 
wait..is the answer zero?
 
yip.
 
eh.. thanks lol! Need to pay attention in class a bit more :)
 
grouchy said:
wait..is the answer zero?

Correctamundo.

Good luck.

Study Tip: Read next week's problems before going to next week's class. Then you know what part of the lecture to snooze through.
 

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