MHB What is the Greatest Integer When Evaluating a Complex Fraction?

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The discussion centers on evaluating the expression $$\left\lfloor{\frac{2014^3}{(2015)(2016)}+\frac{2016^3}{2014(2015)}}\right\rfloor$$. Participants analyze the complex fraction to determine its greatest integer value. The calculations involve simplifying the terms and applying the floor function to find the final result. The conversation emphasizes the shared approach among contributors in solving the problem. Ultimately, the focus remains on accurately evaluating the mathematical expression.
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Evaluate $$\left\lfloor{\frac{2014^3}{(2015)(2016)}+\frac{2016^3}{2014(2015)}}\right\rfloor$$.
 
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anemone said:
Evaluate $$\left\lfloor{\frac{2014^3}{(2015)(2016)}+\frac{2016^3}{2014(2015)}}\right\rfloor$$.

let x = 2015
so we get
$\left\lfloor\frac{(x-1)^3}{x(x+1)} + \frac{(x+1)^3}{(x-1)x}\right\rfloor$
$=\left\lfloor\frac{(x-1)^4+ (x+1)^4}{x(x+1)(x-1)}\right\rfloor$
$=\left\lfloor\frac{2(x^4+6x^2+ 2)}{x(x+1)(x-1)}\right\rfloor$
$=\left\lfloor\frac{2((x^2-1)(x^2+7)+9)}{x(x^2-1)}\right\rfloor$
$=\left\lfloor(\frac{2(x^2+7)}{x}+ \frac{18}{x(x^2-1)})\right\rfloor$
$=\left\lfloor(2x + \frac{14}{x} + \frac{18}{x(x^2-1)})\right\rfloor$
now as x = 2015 and so $\frac{14}{x} < \frac{1}{2}$ and $\frac{18}{x(x^2-1)} < \frac{1}{2}$ so
ans is 2x or 4030
 
Thanks for participating, kaliprasad! Just so you know that my approach is exactly the same as yours. (Smile)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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