What is the Kinetic Energy of the Recoil Electron?

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SUMMARY

The discussion focuses on calculating the kinetic energy of a recoil electron resulting from X-ray scattering. The incident wavelength of the photon is determined to be 4.75 x 10-12 m, with an energy of 1.09 x 10-15 J, while the energy of the scattered photon is calculated to be 1.06 x 10-15 J. To find the kinetic energy of the recoil electron, one must apply the conservation of energy principle, subtracting the energy of the scattered photon from the energy of the incident photon.

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Ok so i got this problem in my physics textbook and I'm just struggling with the last part, please help

X-rays are detected at a scattering angle of 163 and have a wavelength of 0.1867 nm. Find (a) the wavelength of an incident photon, (b) the energy of an incident photon, (c) the energy of a scattered photon and (d) the kinetic energy of the recoil electron



Okie the equations i used are the compton shift equation to determine the wavelength of the incident photon (the x-ray) and also used the equation for energy of a photon to calculate the energy of the incident and scattered photon...but then i got stuck and don't know how to calculate the kinetic energy of the recoil electron:rolleyes:



I got the incident wavelength to be 4.75 x 10^-12 m, the energy of the incident photon to be 1.09 x 10^-15 J and the energy for the scattered photon to be 1.06 x 10^-15 J. I just need to know how to calculate the kinetic energy of the recoil electron

Thanks
 
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You know the energy of the initial photon, and the enegery of the final photon.

Now use the conservation of energy to calculate how much energy the electron will have, and from that the kinetic energy via the usual formula.
 

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