What Is the Mass Percentage of Each Component in a SrCO3 and BaCO3 Mixture?

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The discussion focuses on calculating the mass percentage of strontium carbonate (SrCO3) and barium carbonate (BaCO3) in a mixture weighing 1.60g, which releases 0.421g of carbon dioxide (CO2) upon reaction with hydrochloric acid. The relevant chemical reaction is MCO3(s) + 2H(aq) → M+2(aq) + H2O(l) + CO2(g). By applying stoichiometric principles, one can determine the individual contributions of SrCO3 and BaCO3 to the total mass of the mixture.

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A certain mixture contains only SrCO3 and BaCO3. When 1.60g of this mixture is treated with hydrochloric acid, 0.421g of carbon dioxide gas is liberated. Calculate the mass percentage of each component in the mixture. Reaction of the carbonate with the acid:

MCO3(s)+2H(aq)+--->M+2(aq) + H2O(l) +CO2(g).

Im completely lost on this problem, its kinda the same as the last I guess.

Any help will be appreciated.
 
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