shounakbhatta
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Hello,
Can anybody tell me the meaning of
f:N^n -->N
Can anybody tell me the meaning of
f:N^n -->N
The discussion centers on the notation "f:N^n -->N" and its implications in the context of functions, particularly in relation to the Church-Turing thesis and computability. Participants explore the meaning of n-dimensional sets, the definition of functions, and the computability of functions by algorithms and Turing machines.
Participants generally agree on the basic interpretation of the notation and the definition of n-dimensional sets, but there is disagreement regarding the completeness of the statements about computability and the definition of functions. The discussion remains unresolved on some points, particularly concerning the Church-Turing thesis.
Some statements made by participants are noted to be vague or in need of precision, indicating potential limitations in their understanding or definitions used in the discussion.
arildno said:It probably means a function whose domain is the n-dimensional set of natural numbers, and whose range is the (the 1-dimensional) set of natural numbers.
shounakbhatta said:For every function f: N^n -->N on the natural numbers, f is computable by an algorithm, f is computable by a Turing Machine.
What does it mean?
shounakbhatta said:Ok, understood.
Well, I have one question. In the Church Turing thesis, what is meant by a function?
Whatever we mean like y=f(x), in mathematics, is this a function?
You are right. It was a vague, unconsidered statement of mine in need of your precision. Thanks, Michael.Michael Redei said:What's an n-dimensional set? I think you mean the set of all n-tuples of natural numbers and the set of natural numbers itself, respectively.