I What is the meaning of superposition of momentum in coherent states?

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The discussion centers on the concept of superposition in coherent states, specifically regarding momentum and position. It highlights the distinction between how wave functions are expressed for calculating probabilities of position versus momentum measurements. The superposition reflects the mathematical representation of various probabilities for measurement outcomes. The conversation emphasizes that regardless of the focus on position or momentum, superposition fundamentally represents the different potential results of measurements. Understanding this distinction is crucial for grasping the underlying principles of quantum mechanics.
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What is the meaning of the coherent states superposition of momentum?
Good night. I have a doubt, what is the meaning of the coherent states superposition of momentum?
In a many of places, sites I see an explanation for the equations but I never see the explanation between diffences of the superposition of position from momentum.
 
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physicsradio said:
Good night. I have a doubt, what is the meaning of the coherent states superposition of momentum?
In a many of places, sites I see an explanation for the equations but I never see the explanation between diffences of the superposition of position from momentum.
One way we're writing the wave function in a form that makes it easy to calculate the probability that we'll measure a particular position for the particle if we make a position measurement; the other way we're writing it in a form that makes it easy to calculate the probability that we'll measure a particular momentum for the particle if we make a momentum measurement

But either way, superposition is just the way that the math captures the different probabilities of getting the possible measurement results.
 
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For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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