What Is the Meaning of This Fortran Error Message?

[selmayda]

Hi;
I am trying to run a program which includes;

call AB
write(6,*) 'finished AB'
c---------
call ABp(Vup,gup)
call ABp(Vdn,gdn)
write(6,*) 'finished ABp'
c------------------------------------------------------------------
c do warmup sweeps
c-----

accept = 1
reject = 0

do 410 i = 1, iwarm
call sweep(i)
if (mod(i,10).eq.0) then
write(6,*) 'warmup sweep = ',i
endif
410 continue
write(6, *) 'after warmups, accept ratio = ',
1 float( accept ) / (accept+reject)
write(46,*)
write(46,*) 'after warmups, accept ratio = ',
1 float(accept)/(accept+reject)
c--------------------------------------------------------------------------

but I see an error message ;
multi0.f: In program `multi':
multi0.f:97:
write(6,*) 'accept ratio ='
1
multi0.f:98: (continued):
1 float(accept) / (accept+reject)
2
Invalid radix specifier `float' at (2) for typeless constant at (1)
multi0.f:98:
1 float(accept) / (accept+reject)
1 2
Concatenation operator at (1) must operate on two subexpressions of character type, but the subexpression at (2) is not of character type
mv: cannot stat `a.out': No such file or directory
c----------------------------------------------------------------------

what is the meaning of this message?

thanks.

 

[SteamKing]

It would be helpful to see the entire program.

 

[gsal]

You may want to make your calculation of float(accept)/(accept+reject) previous to the write statement, assign the results to a single variable and print out such variable without any typecasting or anything.

 

[Mark44]

I'm reasoably sure that the errors are cause by these lines of code:

write(6, *) 'after warmups, accept ratio = ',
1 float( accept ) / (accept+reject)[/color]
write(46,*)
write(46,*) 'after warmups, accept ratio = ',
1 float(accept)/(accept+reject)[/color]

Fortran is very picky about splitting lines of code. Either put each write statement on its own line for the entire statement, or use the continuation character, & or +.