MHB What is the measure of angle KPM?

[karush]

ray $\overline{PK}$ bisects the meausre of
$\angle{LPM}$ is $11x^o$ and the measure of $\angle{LPK}$ is $(4x+18)^o$
What is the measure of $\angle{KPM}$

a. $12^o\quad$ b, $28\dfrac{2}{7}^o\quad$ c. $42^o\quad$ d. $61\dfrac{1}{5}^o\quad$ e. $66^o$

ok I think this could be done by observation but that can be a little deceptive
so my eq to solve it was
$2(4x^o+18)=11x^o$
hopefully:unsure:

edit correct the eq

 

[topsquark]

$2(4x^o+36)=11x^o$

Surely you mean 2(4x + 18) = 11x...

-Dan

 

[karush]

$2(4x+18)=11x$
$8x+36=11x$
$36=3x$
$12=x$

$\angle{LPK}$ is $(4(12)+18)^o=(48+18)^o=66^o$ which is e

 

[skeeter]

the little “o” that looks like an exponent is just the degree symbol

 

[karush]

the little “o” that looks like an exponent is just the degree symbol

it might be easier to drop the degree sign when taking steps
but what does x equal?

 

[karush]

the steps to solve this was on the internet but everyone wanted a cc before they would show it.

I really appreciate the help I get here at MHB