What is the measure of angle KPM?

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Discussion Overview

The discussion revolves around finding the measure of angle KPM based on given relationships between angles LPM and LPK. Participants explore the mathematical relationships and equations derived from the angle bisector property.

Discussion Character

  • Mathematical reasoning, Homework-related

Main Points Raised

  • One participant states that ray PK bisects angle LPM, which is given as 11x degrees, and angle LPK is expressed as (4x + 18) degrees.
  • Another participant corrects the equation to 2(4x + 18) = 11x, indicating a need for clarity in the mathematical expression.
  • A participant solves the equation 2(4x + 18) = 11x, leading to x = 12, and calculates that angle LPK measures 66 degrees.
  • There is a clarification regarding the notation used for degrees, with participants noting the confusion caused by the degree symbol appearing similar to an exponent.
  • One participant expresses gratitude for the assistance received in the forum, indicating a reliance on community support for problem-solving.

Areas of Agreement / Disagreement

Participants generally agree on the mathematical approach to solving for x and the relationships between the angles, though there are corrections and clarifications made throughout the discussion. The final measure of angle KPM remains unresolved.

Contextual Notes

There are unresolved aspects regarding the interpretation of the degree symbol and the clarity of the initial equations presented. The discussion also reflects a dependency on community input for solving the problem.

karush
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ray $\overline{PK}$ bisects the meausre of
$\angle{LPM}$ is $11x^o$ and the measure of $\angle{LPK}$ is $(4x+18)^o$
What is the measure of $\angle{KPM}$

a. $12^o\quad$ b, $28\dfrac{2}{7}^o\quad$ c. $42^o\quad$ d. $61\dfrac{1}{5}^o\quad$ e. $66^o$

ok I think this could be done by observation but that can be a little deceptive
so my eq to solve it was
$2(4x^o+18)=11x^o$
hopefully:unsure:

edit correct the eq
 
Last edited:
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karush said:
$2(4x^o+36)=11x^o$
Surely you mean 2(4x + 18) = 11x...

-Dan
 
$2(4x+18)=11x$
$8x+36=11x$
$36=3x$
$12=x$

$\angle{LPK}$ is $(4(12)+18)^o=(48+18)^o=66^o$ which is e
 
Last edited:
the little “o” that looks like an exponent is just the degree symbol
 
skeeter said:
the little “o” that looks like an exponent is just the degree symbol
it might be easier to drop the degree sign when taking steps
but what does x equal?
 
the steps to solve this was on the internet but everyone wanted a cc before they would show it.

I really appreciate the help I get here at MHB
 

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