What is the mechanism of this reaction?

[dr.pharmacy]

hi , I want to ask a question ...

.
What is the mechanism of this rxn ?


CH3CH2OH +MNO2 -------> CH3COOH


I want to help you to find out the mechanism quickly , please

 

[Monique]

What is your attempt at a solution, do you have any idea what it could be?


p.s. only use descriptive titles for new threads, "help me please !" is not appropriate for this forum.

 

[dr.pharmacy]

OK sorry

NO, I do not have any idea to resolve this mechanism...

therefore, I want to help.

thank you

 

[dr.pharmacy]

Any ideas from anyone?
I really need some help on this.

 

[Monique]

First, the equation is not complete. Second, do you think that it could be a redox reaction?

 

[dr.pharmacy]

CH3CH2OH + KMnO4 ------> CH3COOH + H2O + MnO2 + K

yes ,its the type of redox reaction , it is oxidation reaction

i know this but i do not know {How Sicks kmno4 on ethanol to do this reaction{{mechanism}}

(do you understand me?)


thank a lot for anyone help me

 

[dr.pharmacy]

Any ideas from anyone?
I really need some help on this.

 

[dr.pharmacy]

?

 

[dr.pharmacy]

please help me (Monique)

i really need the answer

please

 

[chemisttree]

I don't want to help you! OK?

I hope you don't act like that in the real world...

 

[dr.pharmacy]

Why?

I did not do something for you

I'm new at the Forum

I did not find anyone to help me

(Monique) just helped me from the beginning

(chemisttree)I am so sorry







Accept my apologies

 

[pzona]

Try writing the net ionic equation. This can be very helpful in figuring out exactly which parts of the compounds are oxidized and reduced, which should give you an idea of where to start. You're not getting any help because you haven't demonstrated even the most basic understanding of what you're doing. You need to at least make an attempt at finding a solution yourself; no one wants to just give you an answer. You should at least have an idea of where to start with this.

P.S. Not typing random parts of your posts in giant text might also help.