What is the momentum of the muon in a pi-meson decay?

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Homework Help Overview

The problem involves the decay of a pi-meson at rest into a muon and a neutrino, with specific energy values provided for each particle. The original poster seeks to determine the momentum of the muon resulting from this decay.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy and momentum equations to find the muon's momentum but encounters issues with negative values under the square root in their calculations. Other participants question the source of the equations used and the units of the results obtained.

Discussion Status

The discussion includes attempts to clarify the equations involved and the importance of units in calculations. Some participants provide references to external resources for further understanding. The original poster indicates they have resolved their issue, but no explicit consensus or final solution is presented.

Contextual Notes

Participants are discussing the implications of using specific energy values and the assumptions made regarding the neutrino's mass. There is an emphasis on ensuring correct units throughout the calculations.

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Homework Statement


pi-meson's rest energy is 139.57MeV, it decays into a muon and a neutrino. The muon has a rest energy of 105.45MeV, and a proper lifetime of 2.197*10^-6. The neutrino's mass can be treated as massless in the process.

1) Assuming the pi-meson decays at rest, what is the momentum of the muon?

Homework Equations


E_muon + E_neutrino = E_pi-meson
E_muon = c^2* ((m_pi-meson)^2 - (m_muon)^2)) / (2m_pi-meson)
E_muon = sqrt((P_muon^2 c^2) + (m_muon c^2)^2)

The Attempt at a Solution


Ok I used used the second equation and it gives about 9.866*10^18, then, use this value in the 3rd equation and solving for the momentum, I get a negative value under the square root, which doesn't make sense. In the 2nd equation, the values I plugged in for m_pi-meson and m_muon are just 139.57 and 105.47, and used 3*10^8 for c. Where did I go wrong?
 
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Abdul.119 said:
E_muon = c^2* ((m_pi-meson)^2 - (m_muon)^2)) / (2m_pi-meson)
E_muon = sqrt((P_muon^2 c^2) + (m_muon c^2)^2)
Where do those equations come from?
Abdul.119 said:
Ok I used used the second equation and it gives about 9.866*10^18
9.866*1018 what? Kilometers, apples, ...? Units are important.
 
mfb said:
Where do those equations come from?
9.866*1018 what? Kilometers, apples, ...? Units are important.
The first equation is based on the conservation laws, you can see from here https://teachers.web.cern.ch/teache...h/mbitu/energy_and_momentum_conservation1.htm I used equation (2.5)
For the second equation, I used the fact that E^2 = p^2 c^2 + m^2 c^4 , squared both sides to get E, and tried to solve for the momentum from here
 
Oh never mind, I solved it. Thanks for the help.
 

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