1. The problem statement, all variables and given/known data Ammoniacal nitrogen can be determined by treatment of the sample with chloroplatinic acid; the product is slightly soluble ammonium chloroplatinate: H2PtCl6 + 2NH4 --> (NH4)2PtCl6 + 2H The precipitate decomposes on ignition, yielding metallic platinum and gaseous products: (NH4)2PtCl6 --> Pt(s) + 2Cl2(g) + 2NH3(g) + 2HCl(g) Calculate the percentage of ammonia in a sample if 0.2115g gave rise to 0.4693g of platinum. 2. Relevant equations 3. The attempt at a solution 0.4693(1/(14+1+1+1))= 0.0276 0.0276(2)(159)= 8.778 8.778/0.2115= 41.5% did I do this right? The back of my chemistry book says that the answer should be 38.74% NH3, so if this is correct how would you arrive at this answer?