What Is the Potential of an Ag/Ag+ Electrode in NaCl Solutions?

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SUMMARY

The potential of the Ag/Ag+ electrode in saturated NaCl solutions is calculated using the equation E = E0 + 0.06 log[(Ks)1/2]. The correct pKs value for AgCl is approximately 9.745, leading to a potential of 0.212 V vs ENH when using the correct logarithmic values. For a 3 mol/L NaCl solution, the potential is calculated as E = 0.8 - 0.588 - 0.0286, resulting in 0.183 V vs ENH. These calculations confirm the accuracy of the methods used in the discussion.

PREREQUISITES
  • Understanding of electrochemical cell potentials
  • Familiarity with the Nernst equation
  • Knowledge of solubility product constants (Ksp)
  • Basic chemistry concepts related to ionic solutions
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  • Study the Nernst equation in detail for various electrode systems
  • Explore the solubility product constant (Ksp) calculations for different salts
  • Learn about the behavior of Ag/Ag+ electrodes in various ionic solutions
  • Investigate the effects of concentration on electrode potential
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Chemists, electrochemists, and students studying electrochemical systems will benefit from this discussion, particularly those focusing on electrode potentials and solubility equilibria.

Chris-jap
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Hello everybody

I would like to know the potential of two electrode.

1- The first is the electrode of Ag/Ag+ in a saturated solution of NaCl

I think that the pKs of AgCL is 9.8 (is it right?)
So
E= E0+0.06log[(Ks)1/2]
E=0.8-0.506
E=0.506 vs ENH

Is it correct? (in a book I found a value of 0.2 so...)

2- The second is the electrode of Ag/Ag+ in a solution of NaCl at 3 mol/L this time
so
E=E0+0.06logKs-0.06log[Cl+] ??
E=0.8-0.588-0.0286=0.183 V vs ENH
Is it correct?

Thank you for your help
Chris
 
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Chris-jap said:
Hello everybody

I would like to know the potential of two electrode.

1- The first is the electrode of Ag/Ag+ in a saturated solution of NaCl

I think that the pKs of AgCL is 9.8 (is it right?)
So
E= E0+0.06log[(Ks)1/2]
E=0.8-0.506
E=0.506 vs ENH

Is it correct? (in a book I found a value of 0.2 so...)

The Ksp is 1.8*10^-10, so the pKs comes to around 9.745.

Everything seems right, till "E=0.8-0.506". Shouldn't it be 0.588, as you used in the next question? If you do that, you get E = 0.8-0.588
= 0.212

2- The second is the electrode of Ag/Ag+ in a solution of NaCl at 3 mol/L this time
so
E=E0+0.06logKs-0.06log[Cl+] ??
E=0.8-0.588-0.0286=0.183 V vs ENH
Is it correct?

This appears correct (ofcourse, Cl-).
 

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