Initially there are 45 returns. 15 of them contain errors. 45- 15= 30 do not contain errors. The probability the first selected does not contain errors is 30/45= 2/3. If the first selected contains errors, where are then 44 returns 29 of which contain errors. The probability the second return also does not contain errors is 29/44. If the second selected also does not contain errors then there are 43 returns 28 of which do not contain errors. The probability the third return does not contain errors is 28/43. The probability the three selected returns do not contain errors is (2/3)(29/44)(28/43).