What is the Probability That Two Specific People Will Be on the Same Team?

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SUMMARY

The probability that two specific individuals, A and B, will be on the same team when 35 people are randomly divided into two teams of 10 and 25 is calculated to be 69/119, or approximately 0.58. The analysis considers two scenarios: both individuals being placed in the smaller team of 10 and both being placed in the larger team of 25. The calculations yield a combined probability of 138/238, confirming that the likelihood of A and B being on the same team exceeds 50%.

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Homework Statement



suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the other team contains 25 people. What is the probability that two particular people A and B will be on the same team.


Homework Equations



I don't have the answer on this problem , I am confused. Please help.

The Attempt at a Solution



35 people team C contains 10 people, so the chance to be in this team is 2/7
team D contains 25 people, so the chance is 5/7
when person A is divided in team C , then there is a chance for person B, to be also in this team, namely 9/34(1 person is already divided)
when person B is divided in team D, then there is a chance for person B, to be also in this team, namely 24/34
so there are 2 cases
case 1 has a chance of 2/7*9/34=18/238
case 2 has a chance of 5/7*24/34=120/238
together this is 138/238=69/119 (=0.58) that they are in the same team (the chance is always bigger than 50%)
 
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I get the same answer.
 


Then it is okay. Thanks.
 

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