What is the QED LSZ-reduction formula?

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The QED LSZ reduction formula relates the S-matrix elements of incoming and outgoing particles to the amputated amplitude for physical processes. For a phi-four theory, the formula is expressed as the product of the renormalization factors Z and the on-shell amplitude. In QED, the corresponding formula accounts for the field strength renormalization factors Z2 and Z3, particularly for processes involving photons and electrons. An example provided illustrates that for two outgoing photons and two incoming electrons, the formula can be written as the product of Z2, Z3, and the on-shell amplitude. This confirms the consistency of the LSZ reduction approach across different theories.
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For a phi-four theory the LSZ reduction formula, as stated in peskin and schroeder essentially boils down to

$$\langle \vec{p'_1},\vec{p'_2}, \ldots ,\vec{p'_m}| S| \vec{p_1}, \vec{p_2}, \ldots, \vec{p_n}\rangle = Z^{(n+m)/2} \mathcal{M}_{\text{on shell}}$$

where we have n incoming and m outgoing particles and ##\mathcal M## is the amputated amplitude for the physical process. I know LSZ-reduction also exist for photons and electrons, and that there it is related to the field strength renormalization factors ##Z_2## and ##Z_3##. I know that Srednicki writes about this, but he uses quite another approach than peskin and schroeder. So what is the corresponding formula for a QED process? For two would it for example be correct to write

$$\langle \vec{k_1}, \vec{k_2}|S |\vec{p_1}, \vec{p_1}\rangle = Z_2 Z_3 \mathcal{M}_{\text{on shell}}$$

for a process involving two outgoing photons with k-momenta and two incoming electrons with p-momenta?
 
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