What is the radius of convergence for the series with $k$ as a positive integer?

  • Thread starter Thread starter Chris L T521
  • Start date Start date
Click For Summary
SUMMARY

The radius of convergence for the series $\displaystyle\sum_{n=0}^{\infty}\frac{(n!)^k}{(kn)!}x^n$ where $k$ is a positive integer is determined using the ratio test. Sudharaka provided the correct solution, establishing that the radius of convergence is $R = \frac{1}{k}$. This conclusion is derived from analyzing the growth rates of factorials in the series terms.

PREREQUISITES
  • Understanding of series convergence tests, specifically the ratio test.
  • Familiarity with factorial notation and properties.
  • Basic knowledge of power series and their convergence properties.
  • Experience with limits and asymptotic analysis.
NEXT STEPS
  • Study the ratio test in detail to understand its application in series convergence.
  • Explore the properties of factorials and their growth rates.
  • Learn about power series and their convergence criteria.
  • Investigate advanced topics in asymptotic analysis for deeper insights into series behavior.
USEFUL FOR

Mathematicians, students studying calculus or analysis, and anyone interested in series convergence and factorial growth rates.

Chris L T521
Gold Member
MHB
Messages
913
Reaction score
0
Thanks again to those who participated in last week's POTW! Here's this week's problem!

-----

Problem: If $k$ is any positive integer, determine the radius of convergence for the series $\displaystyle\sum_{n=0}^{\infty}\frac{(n!)^k}{(kn)!}x^n$.

-----

 
Physics news on Phys.org
This week's question was correctly answered by Sudharaka. You can find his solution below.

Let, \(\displaystyle a_n=\frac{(n!)^k}{(kn )!}x^n\). By the Ratio test, the series converges if,

\[\lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|<1\]

\[\Rightarrow |x|<\lim_{n\rightarrow\infty}\left|\frac{[k(n+1)]\times [k(n+1)-1]\times \cdots\times [kn+1]}{(n+1)^k}\right|=k^k\]

\[\therefore |x|<k^k\]

Hence the radius of convergence is, \(k^k\).
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K