What is the radius of convergence for the series with $k$ as a positive integer?

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The radius of convergence for the series ∑(n=0 to ∞) (n!)^k / (kn)! x^n, where k is a positive integer, was determined to be 0. Sudharaka provided the correct solution, explaining the reasoning behind this result. The discussion highlights the importance of understanding factorial growth in relation to convergence. Participants engaged in analyzing the implications of the series' structure on its convergence properties. Overall, the thread emphasizes the mathematical principles involved in determining radius of convergence for series with factorial terms.
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Thanks again to those who participated in last week's POTW! Here's this week's problem!

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Problem: If $k$ is any positive integer, determine the radius of convergence for the series $\displaystyle\sum_{n=0}^{\infty}\frac{(n!)^k}{(kn)!}x^n$.

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This week's question was correctly answered by Sudharaka. You can find his solution below.

Let, \(\displaystyle a_n=\frac{(n!)^k}{(kn )!}x^n\). By the Ratio test, the series converges if,

\[\lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|<1\]

\[\Rightarrow |x|<\lim_{n\rightarrow\infty}\left|\frac{[k(n+1)]\times [k(n+1)-1]\times \cdots\times [kn+1]}{(n+1)^k}\right|=k^k\]

\[\therefore |x|<k^k\]

Hence the radius of convergence is, \(k^k\).
 

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