What is the relationship between frequency and energy in matter waves?

[VHAHAHA]

in my book ,their is a equation

f= E/h

what is the E means?
Total energy?
Does it includes the rest energy ?

 

[ZapperZ]

in my book ,their is a equation

f= E/h

what is the E means?
Total energy?
Does it includes the rest energy ?

This is a good place for you to learn a bit more on how we do things on here.

Never, ever simply quote an equation without proper context.

For example, under what type of discussion was this equation used? Was it trying to explain the energy of photons? Or was it for some other purposes? Have you seen this equation before with regards to photon energy? Etc... etc... Can you see why simply dumping that equation out of nowhere provides us very little to go on with regards to what YOU are seeing in your text?

Zz.

 

[Popper]

in my book ,their is a equation

f= E/h

what is the E means?
Total energy?
Does it includes the rest energy ?

It is not the total energy since it does not include a potential energy term. However it does incluideit does include kinetic energy.

If, h = Planck's constant and f =frequency of matter wave, then

E = "inertial energy" = Kinetic Energy + Rest Energy

 

[Bill_K]

It is not the total energy since it does not include a potential energy term. However it does incluideit does include kinetic energy.

Of course it includes both kinetic and potential energy. A stationary state for a particle in a potential well is described by ψ ~ exp(iEt/ħ) where E is an eigenvalue of H = p²/2m + V(x).

 

[Naty1]

You can read about your equation here as it relates to photons[ light]:

http://en.wikipedia.org/wiki/Energy_of_light#Physical_properties

 

[VHAHAHA]

if the terms includes rest energy
i will not understand the Schrödinger equation
the Schrödinger equ
if the terms includes rest energy i will not understand the Schrödinger equation the Schrödinger equ for free particle
[PLAIN]http://hyperphysics.phy-astr.gsu.edu/%E2%80%8Chbase/quantum/imgqua/seq1.gif
for free particle U=0 and the second term is eliminated
and
http://hyperphysics.phy-astr.gsu.edu/%E2%80%8Chbase/quantum/imgqua/seq2.gif
sub ψ into the Schrödinger equ for free particle
and take the derivative
we got
(ħ^2)(k^2) / 2m = ħw
if E= homework = rel. energy
why can i get (ħ^2)(k^2) / 2m = ħw?
i mean, (ħ^2)(k^2) / 2m = p^2/2m where p is the momentum
and E will be equal to non-rel. KE energy only , but there is no rest energy included!
Plz help =(

STEPS are included


reference: Modern physics second edition , international ed, RANDY HARRIS p.110 - 112

 

[VHAHAHA]

This is a good place for you to learn a bit more on how we do things on here.

Never, ever simply quote an equation without proper context.

For example, under what type of discussion was this equation used? Was it trying to explain the energy of photons? Or was it for some other purposes? Have you seen this equation before with regards to photon energy? Etc... etc... Can you see why simply dumping that equation out of nowhere provides us very little to go on with regards to what YOU are seeing in your text?

Zz.

Actually, i originally think that it refers to KE+rest energy , ie rel. energy
but what i get from the Schrödinger equation for free particles tells that E= non-rel. KE only

you can see the reply for more details. Plz help me, i spend a week to find the ans but i still can figure it out

 

[devilsmaycry]

Isn't the equation E= ħ∨ used for photon

In my knowledge ,
we first calculate λ from λ= ħ/p , then use equation v=λ∨ ==> λ=v/∨
==>
v/∨=ħ/p
==>
∨=pv/h
==>
∨=mv²/h