What is the required force to lift a 15.0 kg child on a teeter-totter?

Thread starter jhrnndz1
Start date Jul 17, 2006
Tags

Torque

Click For Summary

SUMMARY

The required force to lift a 15.0 kg child sitting 1.50 m from the pivot on a teeter-totter is calculated using the principles of torque. The force applied 0.300 m on the opposite side of the pivot must counterbalance the weight of the child. The correct calculation yields a force of 735.8 N, although attention to significant figures is necessary for precision in reporting results.

PREREQUISITES

Understanding of torque and lever principles
Basic knowledge of Newton's laws of motion
Familiarity with significant figures in scientific calculations
Ability to perform calculations involving force and distance

NEXT STEPS

Study the concept of torque in physics
Learn about the application of Newton's second law in rotational dynamics
Review significant figures and their importance in scientific reporting
Explore real-world applications of levers and teeter-totters in engineering

USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of levers and torque in practical scenarios.

Jul 17, 2006

jhrnndz1

I have another question,

A 15.0 kg child is sitting on a plyground teeer-totter, 1.50m from the pivot. What force, applied 0.300m on the other side of the pivot, is need to make the cild lift off the ground?

I got the Force to be 735.8N, is this correct?