What is the Required Speed for a Successful Long Jump Shot?

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Homework Help Overview

The discussion revolves around a physics problem related to projectile motion, specifically calculating the required speed for a long jump shot to successfully reach a basketball hoop from a given height and distance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the launch angles of 30° and 60° and their impact on the required speed. Some participants attempt to apply basic kinematic equations, while others express confusion about their calculations and seek clarification on relevant concepts.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and seeking further guidance on the equations related to projectile motion. There is an indication of varied approaches being explored, but no consensus has been reached yet.

Contextual Notes

Participants are encouraged to refer to textbooks or online resources for additional information on projectile motion, suggesting a reliance on external materials to clarify their understanding of the topic.

kamran93
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long jump shot is released 1.7 m above the ground, 6.03 m from the base of the basket, which is 3.05 m high. For launch angles of 30° and 60°, find the speed needed to make the basket.

_______m/s (30° launch angle)
_______m/s (60° launch angle)
 
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Show relevant equations and your attempts.
 
okay i tried using speed=meters/seconds
but it didn't work.

so i plugged in into an equation
like v=1/2gt^2
 
Go through your textbook or any site and find the information regarding the projectile motion.
 

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