What is the significance of the number 2023?

[jack action]

The new avatar of @fresh_42 is so cool, it deserves its own thread.
$$
\begin{gathered}
(2+0+2+3) \\
\cdot \\
(2^2+0^2+2^2+3^2)^2 \\
= \\
2023
\end{gathered}
$$
Who the heck finds these things?

I don't care about PF rules, I'm calling it: New conspiracy theory ahead!

 

[fresh_42]

The AMS was founded in 1888 to promote mathematical education and research and has approximately 28,000 individuals and 550 institutions as members.

If every hundredth of them tried to find a funny way to write the new year, then there are about 300 mathematicians playing with 2023. I guess the likelihood of finding it is almost certain. Here are more:
https://math.stackexchange.com/questions/4608782/interesting-ways-to-write-2023

 

[fresh_42]

I am still completely astonished by
https://www.physicsforums.com/threads/mathematics-paper-cover-design.891978/post-5611161

 

[fresh_42]

$2023=[A000796]_{10415-10418}$

 

[Ivan Seeking]

I'm sure glad the AMS doesn't make calendars.

 

[fresh_42]

I'm sure glad the AMS doesn't make calendars.

What do you mean?

 

[Ivan Seeking]

What do you mean?

Only mathematicians could figure out the date!

 

[Jarvis323]

And,
$$2024 =2^3 \cdot(23 - 3 - 2^3 - (3^2-2^3 )) \cdot 23$$
It's all connected.

https://en.m.wikipedia.org/wiki/The_Number_23

 

[Ivan Seeking]

45² is coming soon!

 

[PeroK]

Who the heck finds these things?

Whenever you see a number you must factorise it! $2023 = 7 \times 17^2$

You could beat them to it for next year. $2024 = 2^3 \times 11 \times 23$ What can you do with that?

 

[Borek]

Several years ago I wrote a Python program that took all the digits of a birthday date and by some combination of random operations and brute force looked for a way of calculating 666 out from them (not changing the order, using any standard arithmetic operations and parentheses). It wasn't too elaborate but it did the trick.

 

[Hornbein]

Only mathematicians could figure out the date!

I once had a calendar like that. I used an old calendar and corrected it with an offset. My girlfriend didn't like that.

 

[jack action]

Whenever you see a number you must factorise it! $2023 = 7 \times 17^2$

You could beat them to it for next year. $2024 = 2^3 \times 11 \times 23$ What can you do with that?

I really don't have the patience to do this kind of stuff. I will still continue to admire other's people work!

 

[Ivan Seeking]

Several years ago I wrote a Python program that took all the digits of a birthday date and by some combination of random operations and brute force looked for a way of calculating 666

I see! Is this a number you spend a lot of time thinking about?

Do you often smell burning sulfur?

 

[robphy]

Several years ago I wrote a Python program that took all the digits of a birthday date and by some combination of random operations and brute force looked for a way of calculating 666 out from them (not changing the order, using any standard arithmetic operations and parentheses). It wasn't too elaborate but it did the trick.

I’d really like to know how you did that!
(I guess the devil is in the details.)

 

[Borek]

I’d really like to know how you did that!
(I guess the devil is in the details.)

The code is lost in time, but it was based on the eval() function, which takes any expression (in a string form) and calculates its value. Initially I was just plugging +-*/ between digits, later I did some tricks with parentheses as well. The only surviving example I could quickly find is from the earlier version:

10.9.1974 -> 10-9-1+9*74=666

 

[robphy]

I’d really like to know how you did that!
(I guess the devil is in the details.)

By the way, this was a pun.

 

[TonyStewart]

If Mathematicians and Astrologers learned how to read the Mayan Calendar, some might be able to understand how they plotted the alias frequency and phase alignment of planetary cycles which affects Solar Flare cycles from 11 up to 10k yrs or more .

$10^3+ 2^{10} - 10^0= 2023$ ( brainfart corrected)

 

[jack action]

Here we go again for $2025$:
$$(20+25)^2$$
$$(1+2+3+4+5+6+7+8+9)^2$$
$$1^3+2^3+3^3+4^3+5^3+6^3+7^3+8^3+9^3$$

 

[fresh_42]

Here we go again for $2025$:
$$(20+25)^2$$
$$(1+2+3+4+5+6+7+8+9)^2$$
$$1^3+2^3+3^3+4^3+5^3+6^3+7^3+8^3+9^3$$

Not to forget $2025 = 3^4\cdot 5^2$? Can you see the hint? The hidden answer to life, everything, and all the rest?

 

[pines-demon]

Here we go again for $2025$:
$$(20+25)^2$$
$$(1+2+3+4+5+6+7+8+9)^2$$
$$1^3+2^3+3^3+4^3+5^3+6^3+7^3+8^3+9^3$$

Got you covered for 2026 :
$$2026=1^2+(1+2+3+4+5+6+7+8+9)^2$$
$$=1^3+1^3+2^3+3^3+4^3+5^3+6^3+7^3+8^3+9^3$$