- #1
Macleef
- 30
- 0
What is the solution for a limit problem with an indeterminate form of 0/0?
- Thread starter Macleef
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SUMMARY
The discussion centers on resolving the limit problem involving the indeterminate form 0/0 using L'Hopital's Rule. Participants emphasize that when substituting values leads to 0/0, applying L'Hopital's Rule is essential for finding the limit. The technique of multiplying by the conjugate, specifically 2 + sqrt(x), is highlighted as an effective method to simplify the expression and cancel the problematic factors in both the numerator and denominator.
PREREQUISITES- Understanding of limits in calculus
- Familiarity with L'Hopital's Rule
- Knowledge of algebraic manipulation techniques
- Experience with indeterminate forms in calculus
- Study L'Hopital's Rule applications in various indeterminate forms
- Learn about algebraic techniques for simplifying limits
- Explore examples of limits involving square roots and radicals
- Practice solving limit problems that result in 0/0 forms
Students studying calculus, educators teaching limit concepts, and anyone looking to deepen their understanding of resolving indeterminate forms in mathematical analysis.
- #2
Mathdope
- 138
- 0
You should have 0/0 not 6/0. In any case, try a trick similar to what you did with the radical in the denominator.
- #3
workerant
- 40
- 0
Well if you plug the four in initially you get:
2-2/(3-3)=0/0
Your trick did not work nor does using the other radical as Mathdope suggests.
But, never fear, 0/0 limits call for one man...
L'Hopital!
Since it is indeterminate form, it is eligible for L'Hopital's rule. That should make it work.
2-2/(3-3)=0/0
Your trick did not work nor does using the other radical as Mathdope suggests.
But, never fear, 0/0 limits call for one man...
L'Hopital!
Since it is indeterminate form, it is eligible for L'Hopital's rule. That should make it work.
- #4
Dick
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workerant said:
Multiplying by 2+sqrt(x) does so work. You can then cancel the factor that's going to zero in the numerator and the denominator.