What is the solution to POTW #210?

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    2016
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SUMMARY

The discussion centers on the evaluation of the abelianization of the fundamental group of the n-fold connected sum of the projective plane, denoted as $\underbrace{\Bbb RP^2\, \# \cdots \#\, \Bbb RP^2}_{n}$. No participants provided a solution to the Problem of the Week (POTW) #210, prompting the mention of John Lee's solution found in "Introduction to Topological Manifolds," specifically on page 267. This highlights the importance of established literature in addressing complex topological problems.

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  • Understanding of fundamental groups in algebraic topology
  • Familiarity with the concept of abelianization
  • Knowledge of connected sums in topology
  • Basic principles of projective planes, specifically $\Bbb RP^2$
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  • Study the abelianization process in algebraic topology
  • Review John Lee's "Introduction to Topological Manifolds" for insights on fundamental groups
  • Explore connected sums and their implications in topology
  • Investigate the properties of projective planes and their role in topological constructs
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Mathematicians, particularly those specializing in algebraic topology, students studying topological concepts, and educators seeking to enhance their understanding of fundamental groups and connected sums.

Euge
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Here is this week's POTW:

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Evaluate the abelianization of the fundamental group of the $n$-fold connected sum $\underbrace{\Bbb RP^2\, \# \cdots \#\, \Bbb RP^2}_{n}$.
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No one answered this week's problem. This time I'll give someone else's solution -- John Lee's in his book Introduction to Topological Manifolds, on page 267.
Write the fundamental group as $H \cong \langle \beta_1,\ldots, \beta_n\, |\, \beta_1^2\cdots \beta_n^2\rangle$. Let $f$ denote the nontrivial element of $\Bbb Z/2$, and define $\varphi : \operatorname{Ab}(H) \to \Bbb Z^{n-1} \times \Bbb Z/2$ by

$$\varphi(\beta_i) = \begin{cases} e_i, & 1 \le i \le n-1;\\f - e_{n-1} - \cdots - e_1, & i = n\end{cases}$$ By direct computation $\varphi(\beta_1^2\cdots \beta_n^2) = (0,\ldots, 0)$ (noting that $f + f = 0$), so $\varphi$ gives a well-defined map from $H$ that descends to $\operatorname{Ab}(H)$. The homomorphism $\psi : \Bbb Z^{n-1} \times \Bbb Z/2 \to \operatorname{Ab}(H)$ defined by $\psi(e_i) = [\beta_i], \psi(f) = [\beta_1\cdots \beta_n]$ is the inverse for $\varphi$.
 

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