What is the speed of Betty on a playground swing?

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SUMMARY

The discussion focuses on calculating the speed of Betty on a playground swing using principles of energy conservation. Betty's weight is 427 N, and she swings from a height of 0.88 m to 0.22 m above the ground. The potential energy (PE) at the higher position converts to kinetic energy (KE) at the lowest point, leading to the equation PEg = KE. The correct calculation yields a speed of approximately 11.37 m/s when accounting for the correct weight and applying the square root to the final equation.

PREREQUISITES
  • Understanding of gravitational potential energy (PEg = Mgh)
  • Familiarity with kinetic energy equations (KE = 1/2 M V^2)
  • Basic algebra for solving equations
  • Knowledge of gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Review energy conservation principles in physics
  • Learn about the relationship between potential and kinetic energy
  • Study the effects of circular motion on swings and pendulums
  • Practice solving problems involving gravitational forces and motion
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Students studying physics, educators teaching energy conservation, and anyone interested in understanding the mechanics of swings and pendulum motion.

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Homework Statement


Betty weighs 427 N and she is sitting on
a playground swing seat that hangs 0.22 m
above the ground. Tom pulls the swing back
and releases it when the seat is 0.88 m above
the ground.
The acceleration of gravity is 9.8 m/s2 .
How fast is Betty moving when the swing
passes through its lowest position?
Answer in units of m/s.


Homework Equations


KE=1/2 M V^2
PEg=Mgh
i might be missing an equation here


The Attempt at a Solution


i was thinking that potential energy gravitational would turn into Kinetic energy then i solved for v.

PEg= 427 Newtons*.66 i used the change in height for h and got 281.82 Joules for my answer. then i said that should transfer to KE.

281.82 joules= 1/2* 427/9.8 Kg * V^2 and i got 11.3737 m/s as my answer. when i checked this it turned out to be wrong. i think i may have to apply circular motion concepts to this problem, but I'm not quite sure how to do that.

thanks in advance.
 
Last edited:
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Your logic looks sound; it must just be a math error throwing you off... If the work you have here is what you typed into your calculator, then I have two suggestions: first, the weight in the 2nd equation should be 427, not 527... secondly, did you take the square root of both sides at the end? Other than that, I don't know what to tell you.
 
yeah I've got it figured out now thanks.
 

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