What is the trial particular solution for this differential equation?

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dan5
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Homework Statement



y'' + 24y' +432y = cos (wt)

yp(x) = R(h) cos (ht - ∅(h))

find R(h)
and hbar = value for h which R(h) is max.
and ∅(hbar)

Homework Equations



double angle formula for cos
cos (a-b) = cos a cos b + sin a sin b

The Attempt at a Solution



solving the equation as a quadratic in coefficients on sin and cos, hbar = 12
 
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Frankly, I can't figure out what your question is. What is yp? Is it supposed to be a particular solution? If so, you will need to find yp' and yp'' and put them into the equation. What do you get when you do that?
 
yes yp is the particular solution.

Well i thought of using a trial particular solution of

yp= A sin (Ht) + B cos (Ht)

which leaves me with

-AH2-24BH+432A = 0 for coefficients of sin(Ht)

and

-BH2+24AH+432B = 1 for coefficients of cos(Ht)