What Percentage of Random DNA Sequences Does BamH1 Recognize?

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SUMMARY

The discussion centers on calculating the recognition percentage of the restriction enzyme BamH1 for randomly synthesized DNA sequences of length 6 base pairs (bp). The correct answer is determined to be 0.02%, as the probability of randomly generating the specific sequence GGATCC is calculated using the formula (1/4)^6. This confirms that out of all possible 6 bp combinations, only a small fraction corresponds to the BamH1 recognition site.

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  • Understanding of DNA structure and base pairing
  • Knowledge of restriction enzymes and their recognition sites
  • Basic probability calculations
  • Familiarity with nucleotide sequences and codons
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  • Learn about DNA synthesis techniques and their implications for genetic engineering
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Homework Statement



A library of randomly synthesized duplex DNA strands (length = 6 bp) is generated.
What percentage of these sequences would you expect that the restriction enzyme BamH1 (restriction site = GGATCC) would recognize?
a. 0%
b. 0.02%
c. 0.48%
d. 0.07%


Homework Equations


N/A


The Attempt at a Solution


I think that the answer is b, but I'm just looking for confirmation. My reasoning is that there are 4 possible codons, A,T,C,G and so the chance that a randomly synthesized DNA strand of exactly GGATCC would simply be (1/4)^6 or 0.02%
 
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Seems fine to me.
 

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