What physics does this BVP represent?

  • Context: Undergrad 
  • Thread starter Thread starter member 428835
  • Start date Start date
  • Tags Tags
    Physics
Click For Summary
SUMMARY

The boundary value problem (BVP) represented by the equation $$u''(x) = -\lambda u(x)$$ with boundary conditions $$u(0)=u(1)=0$$ describes an oscillating system akin to a mass-spring system governed by Hooke's Law. The general solution is given by $$u = \sum_{n=1} c_n \sin(n\pi x)$$, where the coefficients $$c_n$$ remain undetermined, indicating that the problem is ill-posed without additional conditions. To resolve this, specifying boundary conditions such as $$u(0) = A$$ and $$u'(0) = 0$$ can transform the BVP into an initial value problem (IVP), allowing for a unique solution.

PREREQUISITES
  • Understanding of second-order linear ordinary differential equations (ODEs)
  • Familiarity with boundary value problems (BVP) and initial value problems (IVP)
  • Knowledge of Hooke's Law and simple harmonic motion
  • Basic concepts of oscillatory systems and their physical interpretations
NEXT STEPS
  • Study the derivation and applications of second-order linear ODEs in physics
  • Explore the differences between boundary value problems and initial value problems in detail
  • Investigate the physical implications of boundary conditions in mechanical systems
  • Learn about tuned mass dampers and their design constraints in engineering applications
USEFUL FOR

Students and professionals in physics and engineering, particularly those focused on mechanical systems, oscillatory motion, and differential equations.

member 428835
Hi PF!

What physics does this BVP represent:

$$u''(x) = -\lambda u(x) : u(0)=u(1) = 0$$

Also, I know a general solution is ##u = \sum_{n=1} c_n \sin(n\pi x)##. There is no way of determining ##c_n##; does that mean this problem is ill-posed? I ask about the physics because I'm wondering if there is another equation (depending on what physics this is) that could close the problem.
 
Physics news on Phys.org
  • Like
Likes   Reactions: member 428835 and fresh_42
It is an oscillator, but the boundary conditions leave the amplitude arbitrary.
 
  • Like
Likes   Reactions: member 428835
Thanks for the responses! So what is a physical BC to determine the amplitude?
 
One physical BC is to specify the function u and its first derivative u' at a given value of x. For example,
u(0) = A, u'(0) = 0 will do the job.
 
Chandra Prayaga said:
One physical BC is to specify the function u and its first derivative u' at a given value of x. For example,
u(0) = A, u'(0) = 0 will do the job.
But then it's an IVP and not a BVP.
 
Here's the distinction:

Boundary value problems are similar to initial value problems. A boundary value problem has conditions specified at the extremes ("boundaries") of the independent variable in the equation whereas an initial value problem has all of the conditions specified at the same value of the independent variable (and that value is at the lower boundary of the domain, thus the term "initial" value).

For example, if the independent variable is time over the domain [0,1], a boundary value problem would specify values for {\displaystyle y(t)}
397de1edef5bf2ee15c020f325d7d781a3aa7f50
at both {\displaystyle t=0}
43469ec032d858feae5aa87029e22eaaf0109e9c
and {\displaystyle t=1}
970dea4a5f5ec5355c4cdd62f6396fbc8b1baaa1
, whereas an initial value problem would specify a value of {\displaystyle y(t)}
397de1edef5bf2ee15c020f325d7d781a3aa7f50
and {\displaystyle y'(t)}
ac415aa71b96af9b4e78aea31eff4ba122383095
at time {\displaystyle t=0}
43469ec032d858feae5aa87029e22eaaf0109e9c
.

Finding the temperature at all points of an iron bar with one end kept at absolute zero and the other end at the freezing point of water would be a boundary value problem.

from the wikipedia article:

https://en.wikipedia.org/wiki/Boundary_value_problem
 
jedishrfu said:
Here's the distinction:
from the wikipedia article:

https://en.wikipedia.org/wiki/Boundary_value_problem
Right, so we agree? Also, the oscillating system has time as the independent variable, so initial conditions are used. With boundary conditions, we have ##x## (space) as the independent variable. Do you know if this models any physical system?
 
Yes, your equations model an ideal simple spring sliding back and forth (ie no friction) as long as it stay within the limits and acts according to Hooke's law otherwise all bets are off and the system will either become chaotic or damper out.
 
  • #10
jedishrfu said:
Yes, your equations model an ideal simple spring sliding back and forth (ie no friction) as long as it stay within the limits and acts according to Hooke's law otherwise all bets are off and the system will either become chaotic or damper out.
But then the boundary conditions I impose, those are actually two different moments in time, right? Isn't there a bending beam that behaves similarly, or am I remembering something wrong?

I understand that a mass-spring system is modeled by the ODE, but the BC don't make sense to me in that context (seems an IVP is more appropriate).
 
  • #11
What if an engineer came to you with design constraint boundary conditions for the spring thing?

You may be trying to pidgeon hole this problem too much. Some problem can be described as IVP and at other times as BVP depending on what info you have available to solve it.
 
  • #12
jedishrfu said:
What if an engineer came to you with design constraint boundary conditions for the spring thing?
Can you elaborate please?
 
  • #13
I need a mass damper for a building with the following constraints. I don't want it to sway more than 10 feet in any direction. I want the mass damper to respond to changes as small as X...

https://en.wikipedia.org/wiki/Tuned_mass_damper

This is a made-up example I'm sure the engineers at PF will laugh and provide a much better example.
 
  • #14
Thanks!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
5K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
9K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K