What Power is Needed for Sinusoidal Waves in a Taut Rope?

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SUMMARY

The discussion focuses on calculating the power required to generate sinusoidal waves in a taut rope with mass $M$, length $L$, amplitude $A$, wavelength $\lambda$, and wave speed $v$. The power can be determined using the formula \( P = \frac{1}{2} \mu A^2 \omega^2 v \), where \( \mu \) is the linear mass density of the rope and \( \omega \) is the angular frequency. This formula is essential for understanding wave mechanics in physical systems involving ropes and strings.

PREREQUISITES
  • Understanding of wave mechanics and properties of sinusoidal waves
  • Familiarity with linear mass density and its calculation
  • Knowledge of angular frequency and its relationship to wave speed
  • Basic proficiency in physics equations and problem-solving techniques
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  • Research the derivation of the wave speed formula in taut strings
  • Learn about the relationship between tension and wave speed in ropes
  • Explore applications of wave power calculations in engineering contexts
  • Study the effects of varying amplitude and wavelength on power requirements
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Physics students, engineers, and educators interested in wave mechanics and applications in real-world scenarios involving tensioned materials.

MarkFL
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Hello, MHB Community! (Wave)

anemone has asked me to stand in for her for a few weeks, so please be gentle. (Bigsmile)

Here is this week's POTW:


A taut rope has a mass $M$ and length $L$. What power must be applied to the rope in order to generate sinusoidal waves having an amplitude $A$ and wavelength $\lambda$ and traveling with speed $v$?


Remember to read the https://mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to https://mathhelpboards.com/forms.php?do=form&fid=2!
 
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No one answered this week's problem, and my solution is as follows:

A formula for power $P$ we can apply here is:

$$P=\frac{1}{2}\mu\omega^2A^2v$$

Where:

$$\mu=\frac{M}{L}$$ and $$\omega=\frac{2\pi v}{\lambda}$$

Hence:

$$P=\frac{1}{2}\left(\frac{M}{L}\right)\left(\frac{2\pi v}{\lambda}\right)^2A^2v=\frac{2\pi^2A^2Mv^3}{L\lambda^2}$$
 

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