What Speed Makes Relativistic Momentum 11 Times Nonrelativistic Momentum?

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SUMMARY

The relativistic momentum of a particle becomes 11 times greater than its nonrelativistic momentum at a specific speed, which can be derived from the equation P = mv/(1-v^2/c^2)^(1/2). By setting the Lorentz factor γ equal to 11, the problem simplifies to solving for the velocity v. This relationship highlights the significant impact of relativistic effects on momentum as speeds approach the speed of light.

PREREQUISITES
  • Understanding of relativistic momentum equations
  • Familiarity with the Lorentz factor (γ)
  • Basic knowledge of algebraic manipulation
  • Concept of the speed of light (c)
NEXT STEPS
  • Study the derivation of the Lorentz factor (γ) in detail
  • Explore the implications of relativistic effects on mass and energy
  • Learn about the relationship between velocity and momentum in special relativity
  • Investigate practical applications of relativistic momentum in particle physics
USEFUL FOR

Students of physics, particularly those focusing on special relativity, educators teaching advanced mechanics, and anyone interested in the mathematical foundations of relativistic motion.

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Homework Statement



At what speed is the magnitude of the relativistic momentum of a particle 11 times the magnitude of the nonrelativistic momentum?


Homework Equations



P=mv/(1-v^2/c^2)^1/2

The Attempt at a Solution



11=v/(1-v^2/c^2)^1/2?
 
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Essentially, the question asks you to solve for v, when [tex]\gamma = 11[/tex].
 

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