What Time Achieves Maximum Velocity on a Rollercoaster?

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Homework Statement


The velocity of a a rollercoaster can be described by the fomula "v(t) = -sint + 2sin2t". The interval is 0-5. At what time and what magnitude is maximum velocity achieved?


Homework Equations


v(t) = -sint + 2sin2t


The Attempt at a Solution


v(t) = -sint + 2sin2t
v'(t) = 4cos2t - cost
4cos2t = cost
(not allowed to use graphing calculator)
Answer should be 4.
 
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Write:

[tex] \cos 2t=\cos^{2}t-\sin^{2}t[/tex]

now use [tex]\sin^{2}t+cos^{2}t\equiv 1[/tex] to turn sin into cos and you will be left with a quadratic equation in cos t, solve it.
 
Welcome to PF!

Hi Phoenon! Welcome to PF! :smile:
Phoenon said:
The velocity of a a rollercoaster can be described by the fomula "v(t) = -sint + 2sin2t". The interval is 0-5. At what time and what magnitude is maximum velocity achieved?

Answer should be 4.

Are you sure that's the right question?

2sin2t - sint can't possibly be as much as 4. :redface:
 


tiny-tim said:
Hi Phoenon! Welcome to PF! :smile:Are you sure that's the right question?

2sin2t - sint can't possibly be as much as 4. :redface:

scrap that, I made a mistake