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## Homework Statement

:[/B]A mass is moving with constant acceleration in the x-y plane. At time t = 0s the mass’s position is 2mˆı+3mjˆ, the mass’s velocity is 3 m/s ˆı −4 m / s jˆ and the mass is subject to an acceleration of 1 m/ s ^2 ˆı + 1 m/ s^ 2 i jˆ.

At what time is the velocity perpendicular to the acceleration?

## Homework Equations

:[/B]

v = v0 + α t

x = x0 + v0t + 0.5at^2

v^2= v0^2 +2a(x-x0)

## The Attempt at a Solution

:[/B]

I don't really know how to approach this question. I tried to take the magnitude of velocity and acceleration and find the radius using a= v^2/R, but I don't think that is the way to solve it.

I know that the answer is t=0.5 sec.

Many thanks for your help