What Velocity Does the Sled Reach After 5 Seconds?

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The discussion focuses on calculating the velocity of a sled after being pushed for 5 seconds using Newton's Laws of motion. A force of 300 N is applied, countered by a frictional resistance of 200 N, resulting in a net force of 100 N. Given a combined mass of 50 kg, the sled's acceleration is determined to be 2 m/s², leading to a final velocity of 10 m/s after 5 seconds. The distance traveled by the sled in this time frame is calculated to be 25 meters.

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OK I'm stuk on a physics question involving Newton's Laws of motion.

Question:

Boy gives his sister ride on sled by exerting force of 300 N[E].
Frictional resistance amounts to 200 N. If sister and sled have combined mass of 50 kg, and if boy starts from rest and pushes for 5 sec., find:

a) the sled's acceleration
b) velocity attained by sled in 5 sec.
c) distance traveled by sled in 5 sec.


PLZ try to help and show step by step solutions

Reply ASAP thanx:smile:
 
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It's not the policy here to do peoples homewrok, but I'll give you the relevant formulae:

F = ma, v = u + at, s = ½(u + v)t

F is force, m is mass, a is acceleration ,v is final velocity, u is intial velocity, s is displacemnet and t is time.
 
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Wait, how do we find initial velocity?

Thanx for help.
 
We don't. But since the problem asked for the "velocity attained" (i.e. the increase in velocity), we can take it to be 0- that way the final velocity WILL be the increase in velocity.
 

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