What would be the out of Interp1?

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SUMMARY

The discussion centers on the use of the interp1 function in GNU Octave for one-dimensional interpolation. The command y = interp([1:5 4:9], 1:11, 4) results in an error due to the undefined interp function, while interp1([1:5 4:9], 1:11, 4) successfully returns y = 6. The key takeaway is that the input vector X must be strictly monotonic for interp1 to function correctly, as non-distinct values lead to errors.

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vivek91m
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Hello guys,

If i run the following command

y = interp([1:5 4:9], 1:11, 4);

what would be the output of the same, and what does it mean?
 
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Code:
> y = interp([1:5 4:9], 1:11, 4)
error: `interp' undefined near line 92 column 5
error: evaluating assignment expression near line 92, column 3
... does not exist in gnu octave. How about interp1()?
Code:
> y = interp1([1:5 4:9], 1:11, 4)
y =  6
... which would be the last value calculated for x.
Put Y=11:-1:1 and it gives you

Find out what it means from the help file:
Code:
> help interp1
-- Function File: YI = interp1 (X, Y, XI)
     One-dimensional interpolation. Interpolate Y, defined at the
     points X, at the points XI. The sample points X must be strictly
     monotonic. If Y is an array, treat the columns of Y separately.
... or hunt down the function m-file.
... or just plot Y vs X and see where XI,YI compare.

Presumably you mean - "how does the interpolation function handle the case where the input vectors do not represent a function?"
 
As mentioned in the help:

"The sample points X must be strictly monotonic."

interp1([1:5 4:9], 1:11, 4)

should give an error because x ([1:5 4:9]) is not strictly monotonic here, it doesn't have distinct values. Isn't it?
 

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