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I What would it even mean to consider a "half" derivative?

  1. Dec 21, 2017 #1
    Traditionally, derivatives are taught as a function that have... "Whole" transitions. Take the following example:

    If you have the function f(x) = x^2, we find that f'(x) = 2x, and that f''(x) = 2. In other words, it has a first and a second derivative.

    But what would it even mean to take a rational number as a derivative? I mean... If there is a half derivative for the function of x, you would first imagine instinctively that it's value would between x^2 and 2x, but beyond that I wouldn't know how to imagine what it would be, or what it would imply.

    Is there a derivative for every real number? Imaginary? Are there Partial Half derivatives? What utility do they have? By that I mean, under what circumstance could we use a half-derivative in Physics?
     
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  3. Dec 21, 2017 #2

    TeethWhitener

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  4. Dec 21, 2017 #3

    fresh_42

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    I have never heard of such a thing and I doubt it would make sense. Perhaps if we consider the differentiation as an operator and then expand its rational powers in a series, there is a small chance to even define it properly in some range. But more likely is that we run into problems to define convergence or something like ##D^nD^{\frac{1}{n}}=D## which I would expect to be required.
     
  5. Dec 21, 2017 #4

    DrGreg

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    For sufficiently well-behaved functions, you can use the Fourier transform. Differentiation in the "time domain" corresponds to multiplication by the function ##(\omega \mapsto i \omega)## in the "frequency domain" and that can be generalised to ##(\omega \mapsto (i \omega) ^\alpha)##. It's not something I've ever looked at in detail, so I'm not sure what "sufficiently well-behaved" really means in this context.

    (For A-thead-level readers: more generally, for any operator for which the spectral theorem applies, you can use the ##L^2## representation of the operator.)
     
  6. Dec 25, 2017 #5

    mathwonk

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    this was done by riemann already in complex analysis. the secret is to represent the nth derivative of a holomorphic function, as a Cauchy integral of an expression involving an (n+1)st power. Then since fractional powers make sense, the analogous Cauchy integral formula with a fractional power should be a fractional derivative. thus the one half derivative of f(z) at z=a, should be the integral of f(z)/(z-a)^3/2. Or maybe you also need to know the value of the factorial function at rational numbers, i.e. use the gamma function. in fact that is perhaps the deeper part. I.e. once you can define the factorial function at fractions you get fractional derivatives. You can check this by looking up the cauchy integral formula for a derivative and see if it has a factorial in it. yes it does, so you need to know what (1/2)! means for this question. i.e. gamma(3/2).
     
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