What would the laplace inverse of a laplace be?

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For example:
If F(s) = L{t3e-16tcos(3t)sin2(t)}

What would L-1{F(s)} be?
 
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Jim wah said:
For example:
If F(s) = L{t3e-16tcos(3t)sin2(t)}

What would L-1{F(s)} be?

If ##\mathcal{L}[f(t)] = F(s)##, then ##\mathcal{L}^{-1}[F(s)] = \mathcal{L}^{-1}[\mathcal{L}[f(t)]] = f(t)##
 
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[itex]F(s)= L[t3e^{-16t}cos(3t)sin^2(t)][/itex] seem perfectly reasonable to me. A standard definition of the Laplace transform is
[tex]F<s>= \int_0^\infty e^{-st}f(t)dt</s>[/tex]
so that the Laplace transform of a function of t is a function of s.
 
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