What's the difference between them

  • Context: Graduate 
  • Thread starter Thread starter enricfemi
  • Start date Start date
  • Tags Tags
    Difference
Click For Summary

Discussion Overview

The discussion revolves around the distinction between the notation and the operator |m>

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that represents a number, while |m>
  • There is a question about the nature of the operator, with one participant suggesting it could be represented as pesi(m)pesi(n)*.
  • Another participant describes |m> is akin to a scalar product of vectors.
  • Participants discuss the implications of these representations, noting that does not equal the product of wave functions, and emphasize the importance of not rearranging expressions involving |n>.
  • There is a reiteration of the relationship between the operator and its action on wave functions, with a confirmation of the notation used.

Areas of Agreement / Disagreement

Participants express varying interpretations of the operator and its mathematical implications, indicating that multiple competing views remain. The discussion does not reach a consensus on the exact nature of the operator or its representation.

Contextual Notes

Limitations include potential misunderstandings of the operator's definition and its mathematical properties, as well as the dependence on specific contexts within quantum mechanics.

enricfemi
Messages
195
Reaction score
0
<n|m> ;


|m><n| ;
 
Physics news on Phys.org
<n|m> is a number.
|m><n| is an operator that would act on one wave function to give a different one.
 
appreciate it!

i know the product.
but what the operator is?
is it pesi(m)pesi(n)*?
 
do you mean :
when it act on one wave function,it denotes
|m><n|a> ?
 
Think of it as *all* 1xN matrices
[tex] |n>=A=\begin{pmatrix}<br /> a\\b\\c\\\ldots<br /> \end{pmatrix}[/tex]
[tex] <n|=A^\dag=\begin{pmatrix}<br /> a^* & b^* & c^* & \ldots<br /> \end{pmatrix}[/tex]
[tex] \psi_n(x)=<x|n>[/tex]
Then you see that [itex]|m><n|[/itex] is a matrix ("sort of operator"). [itex]<m|n>[/itex] is a number (like the vector scalar product). Note that [itex]<n|m>\neq \psi_n^*(x)\psi_m(x)[/itex], however since [itex]\sum_x |x><x|=1[/itex]
[tex]<n|m>=\sum_x <n|x><x|m>=\sum_x \psi_n^*(x)\psi_m(x)[/tex]
So
1. don't rearrange |n> expressions
2. only numbers <n|m> commute
3. if you ever get to <x|n>, you can substitute with [itex]\psi_n(x)[/itex]
 
enricfemi said:
do you mean :
when it act on one wave function,it denotes
|m><n|a> ?
Yes...
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
901
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K